Cracking the Code: Solving the Math Problem 2-2×2+2÷2+2²-(2+2)

Hey there, math enthusiasts! Are you ready to tackle a challenging math problem? Today, we're going to break down the solution to the equation 2-2×2+2÷2+2²-(2+2). Don't worry if you're not a math whiz  we'll take it one step at a time.

Can You Solve This Viral Math Problem? 2-2×2+2÷2+2²-(2+2) = ?

The Secret to Solving Math Equations: Order of Operations

When it comes to solving math problems, the order of operations is key. You might be familiar with the acronym PEMDAS, which stands for:

1. Parentheses: Evaluate expressions inside parentheses first.

2. Exponents: Evaluate any exponential expressions next (e.g., 2²).

3. Multiplication and Division: Evaluate multiplication and division operations from left to right.

4. Addition and Subtraction: Finally, evaluate any addition and subtraction operations from left to right.

Let's Get Started!

Now that we know the rules, let's apply them to our equation:

2-2×2+2÷2+2²-(2+2)

Step 1: Evaluate expressions inside parentheses

Inside the parentheses, we have: 2+2 = 4

So, the equation becomes: 2-2×2+2÷2+2²-4

Step 2: Evaluate exponents

2² = 4

Now the equation becomes: 2-2×2+2÷2+4-4

Step 3: Evaluate multiplication and division

2×2 = 4

2÷2 = 1

The equation now becomes: 2-4+1+4-4

Step 4: Evaluate addition and subtraction

From left to right:

2 - 4 = -2

-2 + 1 = -1

-1 + 4 = 3

3 - 4 = -1

The Final Answer

2-2×2+2÷2+2²-(2+2) = -1

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You Did It!

Congratulations on making it to the end! Solving math problems can be challenging, but with practice and patience, you can master even the toughest equations.

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