The Blue, Green and Red Book Tricky Math puzzle solved.

Hi friends today i will show you how to solve this BLUE, GREEN and Book Math puzzle. This puzzle is simple but tricky. Many people failed it when it was first published on our Facebook page.
Here is the puzzle.
If A Blue BookπŸ“˜ and a Blue BookπŸ“˜ and a Blue BookπŸ“˜=6,

A Blue BookπŸ“˜and a Green BookπŸ“— and a Green BookπŸ“—=4,

A Red BookπŸ“• - A Green Book = 2, then
A Green BookπŸ“— and a Red BookπŸ“• divide by a Blue BookπŸ“˜= ?.
Mathematically, this puzzle can summarize as thus:



πŸ“• - πŸ“— = 2

To solve thise, let's solve each of the equation to find the values of each the various caloours of the books.
Started with the first line , you can see that,
3Blue books = 6.
This emplies A Blue Book = 6÷3 ( subject of the formula).
Emplies A Blue Book = 2.

Solving the second line, let's substitute the value of the Blue Book in the equation.
This will be as thus:
2 + 2Green Books = 4.
Emplies 2Green Books = 4 - 2,
2Green Books = 2
Emplies A Green Book = 2÷ 2 = 1.

To solve the third line, let's substitute the value of a Green Book in the equation and see what it gives. 
A Red Book - 1 = 2, This emplies a Red Book is = 3.
Now we have the values of the various colours of the books, let's substitute in the last eequation.
Let me rewrite the last equation to else your understanding.
Green Book +  Red Book ÷ Blue Book = ?
Substituting the values, it will be as thus.
1 + 3 ÷ 2 = ?
Solving this by applying BODMAS, we divide before addition. So , 3 ÷ 2 = 1.5.
1 + 1. 5 = 2.5. The final answer of the puzzle is 2.5. If you have different views please comment.


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